Write the first five terms of the sequence. an=n2 +2

The first five terms of the sequence. an=n2 +2 are 3, 6, 11, 18 and 27.

The sequence is given as n² + 2.

= n² + 2 = 1² + 2 = 1 + 2 = 3

= n² + 2 = 2² + 2 = 4 + 2 = 6

= n² + 2 = 3² + 2 = 9 + 2 = 11

= n² + 2 = 4² + 2 = 16 + 2 = 18

= n² + 2 = 5² + 2 = 25 + 2 = 27

Therefore, the first five terms of the sequence. an=n2 +2 are 3, 6, 11, 18 and 27.

Read related link on:

link

The first five terms of the given sequence

3, 6, 11, 18, 27

Step-by-step explanation:

It is given that,

an=n² +2

To find the first five terms

a₁ = 1² + 2 = 1 + 2 = 3

a₂ = 2² + 2 = 4 + 2 = 6

a₃ = 3² + 2 = 9 + 2 = 11

a₄ = 4² + 2 = 16 + 8 = 18

a₅ = 5² + 2 = 25 + 2 = 27

Therefore the first five terms of the given sequence

3, 6, 11, 18, 27

-4

step-by-step explanation:

the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. hope this ! mark brainliest! you v much! : )