What else would need to be congruent to show that abc=def by the aas theorm?

A. AC≅DF

Step-by-step explanation:

The AAS theorem says that if any two angles and any non-included side of a triangle are congruent to two angles and any non-included side of other triangle then the triangles are congruent.

In the given figure we have ΔABC and ΔDEF, in which

∠A≅∠D

∠B≅∠E

To prove these triangles congruent by AAS theorem , we need one pair of non included side.

i.e. it can be AC≅DF or BC≅EF

AC≅DF is given in the option .

Hence, option A is correct.

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation: