What is the vertex of the quadratic function f(x)=(x-8)(x-2)

Vertex (5 ,-9)

Step-by-step explanation:

Given : Function f(x) = (x – 8)(x – 2).

To find : What is the vertex of the quadratic function .

Solution : We have given that f(x) = (x – 8)(x – 2).

On removing parenthesis

f(x) = x²-2x -8x +16.

f(x) = x²-10x +16.

We need to find vertex of this function ,

Vertex: (h, k)

h = -.

Plugging values

h = -.

h = 5 this is the x- coordinate,

Now , we will plug x= 5 in quadratic function .

k  = (5)²-10(5)+16.

k = 25-50 + 16

k= -9.

Vertex (5 ,-9)

Therefore, Vertex (5 ,-9).

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2