What is the vertex of the quadratic function f(x)=(x-6)(x+2)

vertex = (2, - 16)

Step-by-step explanation:

given

f(x) = (x - 6)(x + 2) ← equate to zero to find the zeros

(x - 6)(x + 2) = 0

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 2 = 0 ⇒ x = - 2

The vertex lies on the axis of symmetry which is situated at the midpoint of the zeros, hence

= = = 2

Substitute x = 2 into f(x) for corresponding y- coordinate of vertex

f(2) = (2 - 6)(2 + 2) = - 4 × 4 = - 16

vertex = (2, - 16)

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.