2x+y=8
y+3z=5
z+2w=1
5w+3x=9

find the solution to each variable

  w = 0, x = 3, y = 2, z = 1

Step-by-step explanation:

You can use each equation to write an expression that will substitute into the next equation.

  y = 8 -2x . . . . from the first equation

  8 -2x + 3z = 5 . . . . . substituted into the second equation

  z = (-3 +2x)/3 . . . . . solved for z

  (-1 +2/3x) +2w = 1 . . . . . substituted into the third equation

  w = (2 -2/3x)/2 . . . . . solved for w

  5(1 -1/3x) +3x = 9 . . . . . substituted into the last equation

  4/3x = 4 . . . . . simplified, 5 subtracted

  x = 3 . . . . . . . . multiply by 3/4

  w = 0 . . . . . . . .value of x substituted into equation for w

  z = 1 . . . . . . . . value of x substituted into equation for z

  y = 2 . . . . . . . .value of x substituted into equation for y

The solution is (w, x, y, z) = (0, 3, 2, 1).

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

step-by-step explanation: