Find two numbers if their sum is six and their difference is 36

Step-by-step explanation:

Let the two numbers be x and y

x + y = 6

x - y = 36       Add the two equations.

2x = 42          Divide by 2

2x/2 = 42/2

x = 21

x + y = 6         Substitute for x

21 + y = 6        Subtract 21

21-21 + y = 6-21

y = - 15

how is that middle school

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.