Four friends are waiting in line. how many different ways can they arrange themselves in that line?

(5)(4)(3)(2)(1)= 120. your answer will be 120

Step-by-step explanation:

Step-by-step explanation:

Say their names are A,B,C,and D.

You can put A,B,C,D.

D,C,B,A

C,D,B,A

C,D,A,B

C,A,D,B

C,A,B,D

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.