The function f(x) = x^2 +8x+10 is equivalent to the function f(x)=(x-h)^2+k. what is the value of h and k . at what value of x is the minimum value of the function

ANSWER

Minimum value: y=-6

Occurs at: x=-4

EXPLANATION

Given

We need to write the equivalent of this function in vertex form:

where (h,k) is the vertex.

We must complete the square to get the function to this form.

We add and subtract the square of half the coefficient of x.

This gives us;

The first three terms form a perfect square quadratic trinomial.

or

Therefore we compare to

h=-4 and k=-6

The minimum value of the function is

and this occurs at;

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