How much would the statue weigh if the original was 10
feet?

Part a) The weight of the original statue is

The ratio of the height of the original statue to the height of the small statue is 8.4

The ratio of the weights or volumes is

Part b)  

Step-by-step explanation:

Part a)

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor and the ratio of its volumes or weights is equal to the scale factor elevated to the cube

step 1

Find the scale factor

remember that

The original statue is 7 ft tall

Convert to inches

Divide the height of the original statue by the height of the model to find the scale factor

step 2

Find the ratio of its weights

Let

z-----> the scale factor

x-----> the weight of the original statue

y----> the weight of the model

so

we have

substitute

The weight of the original statue is

The ratio of the height of the original statue to the height of the small statue is 8.4

The ratio of the weights or volumes is

Part b) If the original statue were 20 ft tall, how much would it weight?

step 1

Find the scale factor

remember that

The original statue is 20 ft tall

Convert to inches

Divide the height of the original statue by the height of the model to find the scale factor

step 2

Find the ratio of its weights

Let

z-----> the scale factor

x-----> the weight of the original statue

y----> the weight of the model

so

we have

substitute

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2