Aroom has three lightbulbs. each one has a 10% probability of burning out within the month.

what is the probability that at the end of the month at least one of the bulbs will be lit?

10% probability of burning out within a month

100-10 = 90% chance of not burning out within a month

90% = 0.9

(0.9)*(0.9)*(0.9) = (0.9)^3 = 0.729 = 72.9%

The probability that all 3 stay lit at the end of the month is 72.9%

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!