The figure abcd is made up of two different triangles. abd is a right-angled triangle. ab=25 cm, ad=60 cm, bd=65 cm and ce=45 cm. find the area of figure abcd.

2212.5 cm²

Step-by-step explanation:

ABCD is constructed from 2 right triangles ABD and BCD

The area (A ) of a triangle is calculated using the formula

A = bh ( b is the base and h the perpendicular height )

In ΔABD, b = AD = 60 and h = AB = 25, hence

A = × 60 × 25 = 30 × 25 = 750 cm²

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In ΔBCD, b = BD = 65 and h = CE = 45, hence

A = × 65 × 45 = 1462.5 cm²

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The area of figure ABCD = area of ΔABD + area of ΔBCD

A = 750 + 1462.5 = 2212.5 cm²

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )