Brendan is planning a trip to germany. he is trying to decide which cities to visit during his stay. the following table shows potential cities he could visit, as well as what he expects to pay for lodging, transportation, and similar expenses in each one. all costs are given in euros (€). city cost (€) berlin 171 wiesbaden 263 hanover 169 dresden 215 kiel 209 stuttgart 297 potsdam 179 munich 159 brendan's original plan was to visit stuttgart, dresden, weisbaden, and berlin. however, he would like to keep his costs under €860. which of the following changes would be the cheapest swap that brendan can make and stay under budget?
a. replace dresden with potsdam.
b. replace stuttgart with kiel.
c. replace berlin with munich.
d. replace weisbaden with hanover.
select the best answer from the choices provided
a
b
c
d

Option B

Budget  858€

Step-by-step explanation:

City   -  Cost (€)

Berlin 171

Wiesbaden 263

Hanover 169

Dresden 215

Kiel 209

Stuttgart 297

Potsdam 179

Munich 159

Cost of original plan

Stuttgart + Dresden + Weisbaden + Berlin  =

297€ + 215€ + 263€ + 171€  = 946 €

Lets evaluate the options to see which one can get the budget under 860€

a) Replace Dresden with Potsdam

Postdam - 179€

297€ +(179)€ + 263€ + 171€  = 910€

Not the correct choice

b) Replace Stuttgart with Kiel.

Kiel 209€

(209)€ + 215€ + 263€ + 171€  = 858€

Correct choice

in 2010, the population of the state of california is 37.29 × 10⁶

step-by-step explanation:

population of los angeles = 3.79 × 10⁶

population of california = 9.84 × population of los angeles

                                        = 9.84 × 3.79 × 10⁶

                                        = 37.2936 × 10⁶

                                        = 37.29 × 10⁶

∴ in 2010, the population of the state of california is 37.29 × 10⁶