What is the frequency of the function f(x)?

f(x)=3cos(5x)+2

enter your answer, in simplest fraction form, in the box.

The frequency = 5/2π

Step-by-step explanation:

* Lets revise some facts about the trigonometry function

- If the function is f(x) = A sin (B x + C) + D  

* A is the amplitude  

- The amplitude is the height from highest to lowest points and  

 divide the answer by 2  

* The period is 2π/B  

- The period is the distance from one peak to the next peak

- Period and Frequency are related where frequency = 1/period

* C is the horizontal shift  

- The horizontal shift is how far the function is shifted to left  

 (C is positive) or to right (C is negative) from the original position.  

* D is the vertical shift  

- The vertical shift is how far the function is shifted vertically up

  (D is positive) or down (D is negative) from the original position.  

* Lets solve the problem

∵ f(x) = 3 cos (5x) + 2

∵ f(x) = A sin (B x + C) + D  

∴ A = 3 , B = 5 , C = 0 , D = 2

∵ The period = 2π/B

∴ The period = 2π/5

∵ The frequency = 1/period

∴ The frequency = 1/(2π/5) ⇒ multiply up and down by 5

∴ The frequency = 5/2π

they are simplified

step-by-step explanation:

the radius is 2 times the diameter.

step-by-step explanation: