What are the x intercepts of the quadratic function? y=-x^2+2x-1

x = 1

Step-by-step explanation:

Given in the question the equation

y = -x² + 2x - 1

To find the x-intercept, substitute in 0 for y

0 = -x² + 2x - 1

To find value of x use quadratic equation

x = -b ± √b²-4ac / 2a

  here a = -1

           b = 2

           c = -1

x1 = -2 + √2²-4(-1)(-1) / 2(-1)

   = -2 + 0 / -2

   = -2 / -2

   = 1

x2 = -2 - √2²-4(-1)(-1) / 2(-1)

   = -2 - 0 / -2

   = -2 / -2

   = 1