2cars are driving in a highway. car a starts 10 miles ahead of car b. car a is driving at a speed of 55 miles per hour. car b is driving at a speed of 60 miles per hour. after how many hours will the 2 cars be in the same location? how far will car b have driven when the 2 cars leer?

Step-by-step explanation:

60 - 55 = 5, car B catches up to Car A 5 miles per hour, they are 5 miles closer every hour

10 / 5 = 2, 2 hours

car b would have driven 60 * 2 = 120

the first question mark is 6 and the second question mark is 26 (the square root)

step-by-step explanation:

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: