In the figure, lines m and n are parallel to each other. lines p and q are also parallel to each other.

the value of x is degrees, and the value of y is degrees.

The value of X is 112° and The value of Y is 68°

Angle y: 68°

Angle x: 112°

Step-by-step explanation:

When you are dealing with two sets of parallel lines where one set intercepts the other, angles are always the same as the parallel line's angle. In this example

∡PM = 68° = ∡y°

Seeing that we now know that y is 68° and q is a straight line (Straight Lines have an angle of 180°) we can subtract 68° from 180° in order to get the degree of the angle x.

180° - 68° = 112°

Now we know that angle y is 68° and angle x is 112°

I hope this answered your question. If you have any more questions feel free to ask away at .

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!