Find an equation of variation where y varies directly as x and y=500 when x=50.

y

=

8

Step-by-step explanation:

Explanation:

the initial statement is  

y

∝

x

to convert to an equation multiply by k the constant

of variation

⇒

y

=

k

x

to find k, use the given condition for x and y

y

=

10

when  

x

=

5

y

=

k

x

⇒

k

=

y

x

=

10

5

=

2

the equation is  

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

y

=

2

x

2

2

∣

∣

∣

−−−−−−−−−−−  

x

=

4

→

y

=

2

×

4

=

8

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.