What is the center of the circle given by the equation (x−6)2+(y+3)2=72? a. (-6, 3) b. (-3, 6) c. (6, -3) d. (6, 7)

The center of the circle is the x and y in the equation.

To find the center you need to solve for x and Y when the equations inside parenthesis are set to zero.

(x-6)=0

x = 6

(y+3)=0

y = -3

The center of the circle is (6,-3)

idk

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )