Mathematics, 04.02.2020 21:59 mrwiggles675
Ineed with a calculus 2 exercise, with a good explanation to what i'm trying to figure out.
the problem involves finding the arc length when y = (x^2)/2 - (lnx/4) given 2≤ x ≤ 4
so i know the formula involves l = integral from a to b of sqrt(1+(f'(x))^2)dx
and i took the the derivative of y = (x^2)/2 - (lnx/4)
and got = x - (1/4x)
i then kept reducing it to suit the formula
1 + ( x - 1/4x)^2
i added the alike terms
1 + x^2 - 1/2 + 1/16x^2
x^2 + 1/2 + 1/16x^2
and then comes my question!
so it is supposed to become this afterwards: (x + 1/4x) ^ 2
but how did that happen, i don't understand how i can reduce it to a square, me figure it out.
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