1. rank the following from largest mass to smallest mass.
gravity on the moon = 1.6 m/s^2 gravity on mars = 3.7 m/s^2
a) 1 kg object on earth
b) 2.75 lbm object on the moon
c) 1.25 lbf object on the moon
d) 15 n object on earth
e) 15 n object on mars

e) 15 N object on Mars

d) 15 N object on earth

b) 2.75 lbm object on the moon

a) 1 kg object on earth

c) 1.25 lbf object on the moon

Step-by-step explanation:

Mass is the amount of mass that a certain object has, it differs from its weight because the weight depends of the gravity or the force that is been applied to the object towards the planet.

To obtain the mass a 15N object on mars you have to divide the 15N by the gravity of mars this would be like this:

Mass:= 4.05kg

To obtain the mass of a 15 N objecto on the earth you divide 15N by 9.8 which is the gravity on earth.

Mass:= 1.53 kg

To calculate the mass of a 2.75 lbm object on the moon you just have to convert it to kg.

Mass in kg: 2.75*.453= 1.24  kg

Then the 1 kg mass object on the earth.

And last the 1.25 lbf object on the moon you just convert it to kilograms.

Mass in kg: 1.25*.138=.172kg

the answer is 489

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.