Acircle is centered at the point -3 2 and passes through the point 1 and 5 the radius of the circle is blank units

The radius of the circle is 5 units

Step-by-step explanation:

Given in the question,

centered point = (-3 , 2)

a point in the circle = (1,5)

To find the radius of circle we will use the circle equation

(x – h)² + (y – k)² = r²,

with the centre being at the point (h, k) and the radius being r.

Plug values in the equation

(1 – (-3))² + (5 – 2)² = r²

(1+3)² + (3)² = r²

4² + 3² = r²

25 = r²

r = √25

r = 5

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,