Write two mixed numbers where the lcd is 12, but the product of the denominators in not 12?

Step-by-step explanation:

The prime factorization of 12 is

 12 = 2²×3

To find denominators suitable for your purpose, you need to group the factors

 {1, 2, 2, 3}

into two groups with different products that share at least one of the numbers that is not 1.

For example, your grouping could be (2, [2), 3], where a 2 is shared. That is, your denominators could be 2*2=4 and 2*3=6.

Another possible grouping is (1, [2), 2, 3], giving rise to denominators of 2 and 12.

Yet another is (1, [3), 2, 2], for denominators of 3 and 12.

Using the first grouping, a pair of mixed numbers matching your requirement might be

 1 3/4, 5 1/6

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

answer: okw

step-by-step explanation: