For the function f(x) = -2(x + 3)^2 -1, identify the vertex, domain, and range. a.) the vertex is (3, -1), the domain is all real numbers, and the range is y ≥ -1. b.) the vertex is (3, -1), the domain is all real numbers, and the range is y ≤ -1. c.) the vertex is (-3, -1), the domain is all real numbers, and the range is y ≤ -1. d.) the vertex is (-3, -1), the domain is all real numbers, and the range is y ≥ -1

answer: c

step-by-step explanation: because you don't have to draw a point of intersection. couldyou give me brainliest?

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answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

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