Solve the equation. x^2 − 6x − 7 = 0
a) x = 7
b) x = 1
c) x = 1 or x = −7
d) x = −1 or x = 7

D

Step-by-step explanation:

given x² - 6x - 7 = 0 ← in standard form

To factor the quadratic

Consider the factors of the constant term ( - 7 ) which sum to give the coefficient of the x- term ( - 6)

The factors are - 7 and + 1, since

- 7 × 1 = - 7 and - 7 + 1 = - 6, thus

(x - 7)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 1 = 0 ⇒ x = - 1

The solution to the equation is D

answer: finding the extract measurements and knowing the points

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.