An egg is dropped from a height of 90 ft. if acceleration die to gravity is -16ft/s^2 and initial velocity is 0ft/s, approximately how long will it take for the egg to reach the ground?

t = time

Multiply the acceleration by time and add to the height:

The equation becomes H(t) = -16 * t^2 + 90

set h(t) to 0

0 = -16*t^ +90

Subtract 90 from both sides:

-90 = -16*t^2

divide both sides by -16:

t^2 = -90 / -16

t^2 = 5.625

t = √5.625

t = 2.37 seconds, round to 2.4 seconds.

0,0

step-by-step explanation:

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )