Mathematics, 05.02.2020 00:50 alyssanewsome

There are 36 gold cards and 36 silver cards in a deck. the gold cards are numbered 1,3, 71 and the silver cards are numbered 2.4. 72. the cards are throughly shuffled and one card is randomly selected.

a. find the probability of selecting a gold card or a card with a multiple of 12 on it. show your work

b. find the probability of selecting a silver card or a card with a multiple of 9 on it. show your work.

Answers: 3

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Answers

Answer from: multezemaleme

A) multiples of 12 up to 72 ( 72 total cards)

12, 24, 36, 48, 60, 72 = 6 cards.

36 are gold.

Total gold cards and multiple of 12 = 36 + 6 =42

Probability of getting one of them is 42/72, which reduces to 7/12

B) 36 silver cards

Multiples of 9: 9, 18, 27, 36, 45, 54,63 = 7 cards

Silver cards are even and there is 3 even cards that are also multiples of 9, so subtract 3 from 7 to get 4.

Total silver cards and multiples of 9 = 36 + 4 = 40

Probability = 40/72 which reduces to 5/9

Answer from: kdawg203

Step-by-step explanation:

Because there is no overlap between good card and card with a multiple of 12,

P(gold card or a card with a multiple of 12)

= P(gold card) + P(a card with a multiple of 12)

P(gold card)

= no. of gold cards / total no. of cards

= 36 / (36 + 36)

= 36 / 72

= 1/2

P(a card with a multiple of 12)

= no. of cards with multiples of 12 / total no. of cards

= (12, 24, 36, 48, 60, 72) / 72

= 6/72

= 1/12

P(gold card or a card with a multiple of 12)

= 1/2 + 1/12

= 7/12

B. There ARE overlaps between a silver card and a card with a multiple of 9,

P(silver card or a card with a multiple of 9)

= P(silver card) + P(a card with a multiple of 9) - P(silver card AND a multiple of 9)

P(silver card)

= no. of silver cards / total no. of cards

= 36 / (36 + 36)

= 36 / 72

= 1/2

P(a card with a multiple of 9)

= no. of cards with multiples of 9 / total no. of cards

= (9, 18, 27, 36, 45, 54, 63, 72) / 72

= 8/72

= 1/9

P(silver card AND a multiple of 9)

= no. of silver cards AND a multiple of 9 / total no. of cards

= (18, 36, 54, 72) / 72

= 4/72

= 1/18

P(silver card or a card with a multiple of 9)

= 1/2 + 1/9 - 1/18

= 10/18

= 5/9

Answer from: Quest

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

() click an item in the list or group of pictures at the bottom of the problem and, holding the butt

Answer from: Quest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

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