Kurt spots a bird sitting at the top of a 40 foot tall telephone pole. if the angle of elevation from the ground where he is standing to the bird is 59 degrees, how far is kurt standing from the base of the pole?

angle of elevation, aoe = 59 deg

height, h = 40ft

distance from pole, dfp

using

tan 59deg = h/dfp

=》 dfp = h/ tan 59deg = 40/1.67 = 23.95ft

24.04 ft

Step-by-step explanation:

Kurt spots  a bird sitting at the top of a 40 foot tall telephone pole

Consider the right triangle formed by the line joining the base of telephone pole and Kurt's leg,  the pole itself and line joining Kurt leg and top of pole.

This is right angled and since angle of elevation is given as 59

we have

height of pole/distance of Kurt from base = tan 59

i.e.

where d is the required distance of Kurt from the pole.

Hence x = 24.038

=24.04 feet

i am unable to solve this problem

step-by-step explanation:

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743