What is the value of f(? 3) +f(7) f(-3) +f(7) when f(x)=? 3x+9 f(x)=-3x+9 ? 18 6 -6 -12

The correct answer is 6.

Step-by-step explanation:

To find this, first find f(-3)

f(x) = -3x + 9

f(-3) = -3(-3) + 9

f(-3) = 9 + 9

f(-3) = 18

Now we do the same for f(7)

f(x) = -3x + 9

f(7) = -3(7) + 9

f(7) = -21 + 9

f(7) = -12

Now we add them together

18 + -12 = 6

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150