Mathematics, 05.02.2020 05:56 Fire1099

Consider the following expression and the simplified expression. expression simplified expression 3x^2+5y +3 +4y^2+6 9x^2-7^2+9 which terms could be in the boxes to make the expressions equivalent?

Consider the following expression and the simplified expression. expression simplified expression 3x

Answers: 2

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Answer from: david2154

+6x^2 and -10y^2

Step-by-step explanation:

Let's go one term at a time from the right side and match it with the left side.

On the right hand side, we have 9x^2

. On the left side we have 3x^2

. So we would need a 6x^2

. Hence we can eliminate option C and D immediately.On the right hand side, we have -y^2

. On the left side we have 5y^2

and

, which is equal to 9y^2

. So we would need to subtract 10y^2

to make right hand side into -y^2

Clearly Option B is right.

Answer from: tristan4233

The correct answer option is +6x^2 and -10y^2 .

Step-by-step explanation:

We are given the following incomplete expression:

3 x^2 + 5 y^2 __ + 3 __ + 4 y^2 + 6

and then there is its simplified expression as shown below:

9 x^2 - y^2 + 9

We are to determine whether which terms could be in the boxes to make the expressions equivalent.

+6x^2 and -10y^2 are the two terms which justify the given expression:

3 x^2 + 5 y^2 +6x^2 + 3 -10y^2 + 4 y^2 + 6 = 9 x^2 - y^2 + 9

Answer from: Quest

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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