Given that the points (-5,7), (5,,1), and (-5,1) are vertices of a rectangle, how much stronger is the width than the length

  4 units

Step-by-step explanation:

The sides of the rectangle are parallel to the axes, so it is a simple matter to subtract coordinate values to find the dimensions.

Along the line y=7, the rectangle extends from -5 to 5, so has width 10.

Along the line x=5, the rectangle extends from 1 to 7, so has length 6.

The width is 10 - 6 = 4 units more than the length.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: it's a

step-by-step explanation: