What is the equation of the line that passes through (0,3) and (-5,3)

y = 3

First find the gradient of the line:

(Y²-Y¹)/(X²-X¹)

(3-3)/(-5-0)

0/-5 = 0

Your gradient is 0

Now find the y intercept. This is whrre where the line crosses the y axis, when X = 0

(0,3)

Your y intercept is 3.

Now put It into the formula y = mx + c

m = 0

c = 3

y = 0x + 3

y = 0 + 3

y = 3

l.ln.lln.k.nkl

step-by-step explanation: