So much if u do

janette went to tire mart and paid $122.57 per tire for 4 tires and a flat rate fee for installation for a total of $555.28 before taxes. monique went to fast wheels and paid $136.71 per tire for 4 tires and a flat rate fee for installation for a total of $585.34 before taxes. the difference in the amount that they paid in installation charges is $

$65

Step-by-step explanation:

Let's add up the flat rate and the cost of four tires:

flat rate + 4($122.57/tire) = $555.28

We are to solve for "flat rate."  First, multiply out 4($122.57/tire), obtaining a tire cost of $490.28 total.  Subtracting this tire cost from the $555.28 Janette paid the shop, we get "flat rate" = $555.28 - $490.28, or $65.

Thus, the installation charge ("flat rate") must have been $65.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: