![\bf cot(x)cos(x)-cot(x)=0\implies cot(x)[cos(x)-1]=0 \\\\[-0.35em] ~\dotfill\\\\ cot(x)=0\implies \cfrac{cos(x)}{sin(x)}=0\implies cos(x)=0\\\\\\ x=cos^{-1}(0)\implies \boxed{x= \begin{cases} \frac{\pi }{2}\\\\ \frac{3\pi }{2} \end{cases}} \\\\[-0.35em] ~\dotfill\\\\ cos(x)-1=0\implies cos(x)=1\implies x=cos^{-1}(1)\implies \boxed{x=0}](/tpl/images/0400/1977/b186a.png)
cotxcosx - cotx = 0
0
pi/2
Mathematics, 03.12.2019 01:31 nia3378
Solve for x for 0 ≤ x < 2 π .
cotxcosx - cotx = 0
0
pi/2
pi
3pi/2
2pi
Answers: 2
Another question on Mathematics
Mathematics, 21.06.2019 17:30
Me with this one question, and i'll upvote the brainliest answer
Answers: 2
Mathematics, 21.06.2019 18:30
Suppose your school costs for this term were $4900 and financial aid covered 3/4 of that amount. how much did financial aid cover? and how much do you still have to pay?
Answers: 1
Mathematics, 21.06.2019 20:00
Find the value of x. give reasons to justify your solutions! l, m ∈ kn
Answers: 3
Mathematics, 22.06.2019 00:00
Determine the function’s value when x = -1 a. g(-1)=-3 b. g(-1)=0 c. g(-1)=1 d. g(-1)=27
Answers: 2
You know the right answer?
Solve for x for 0 ≤ x < 2 π .
cotxcosx - cotx = 0
0
pi/2
cotxcosx - cotx = 0
0
pi/2
Questions
Business, 25.11.2020 19:20
History, 25.11.2020 19:20
Mathematics, 25.11.2020 19:20
Spanish, 25.11.2020 19:20
Arts, 25.11.2020 19:20
Mathematics, 25.11.2020 19:20
English, 25.11.2020 19:20
Mathematics, 25.11.2020 19:20
Mathematics, 25.11.2020 19:20
Social Studies, 25.11.2020 19:20
