Acircle is centered o (0,0) and has the radius 3.46410161514 where does poing m (-3,2) lie

outside the circle

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← r is the radius = 3.46410161514, hence

x² + y² = 3.46410161514²

x² + y² = 12 ← equation of circle

To determine where a point (x, y) lies

• If x² + y² < r² then point is inside the circle

• If x² + y² = r² then point lies on the circle

• If x² + y² > r² then point lies outside the circle

For (- 3, 2)

(- 3)² + 2² = 9 + 4 = 13 > 12

Hence point (- 3, 2) lies outside the circle

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )