Need length of a rectangle is 5 cm longer than the width. four squares are constructed outside the rectangle such that each of the squares share one side with the rectangle. the total area of the constructed figure is 120 cm2. what is the perimeter of the rectangle?

The perimeter of rectangle is

Step-by-step explanation:

Let

x-----> the length of the rectangle

y----> the width of the rectangle

we know that

----> equation A

---> equation B (area of the constructed figure)

substitute the equation A in equation B

using a graphing tool -----> solve the quadratic equation

see the attached figure

The solution is

Find the value of x

---->

Find the perimeter of rectangle

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

you divide the cost ($15) by the quantity (6) to get your questions answer. the yo-yo costs $2.50. hope this : )!

step-by-step explanation: