Raul bought a soft drink and a sandwich for $9.90. what is the price of each if the sandwich cost 3.5 times as much as the soft drink?
a) sandwich costs $5.94 and the soda costs $3.96
b) sandwich costs $7.70 and the soda costs $2.20
c) sandwich costs $5.40 and the soda costs $4.50
d) sandwich costs $2.83 and the soda costs $9.90

First create a ratio:

The sandwich cost 3.5 more than the drink therefore the ratio is 3.5:1

Then add the two sides of the ratio together to get the total parts of the ratio
3.5+1 = 4.5

Now that we know the total parts of the ratio we can solve for one part by dividing the total cost $9.90 by the total parts of the ratio 4.5+

$9.90/4.5 = 2.20

Since we know that each part of the ratio is 2.20 we multiply both sides of the ratio by 2.20

3.5 *2.20 = 7.70
1 * 2.20 = 2.20

Therefore the answer is B