1. 6, 11, 16, 21, 26
2. aβ = 14, aβ = aβββ - 4
Step-by-step explanation:
1. First 5 terms
Β Β Β Β aβ = 5n + 1
n = 1: aβ = 5 Γ 1 + 1 = Β 6 + 1 Β = Β 6
n = 2: aβ = 5 Γ 2 + 1 = 10 + 1 = 11
n = 3: aβ = 5 Γ 3 + 1 = 15 + 1 = 16
n = 4: aβ = 5 Γ 4 + 1 = 20 + 1 = 21
n = 5: aβ
= 5 Γ 5 + 1 = 25 + 1 = 26
The first five terms of the sequence are
6, 11, 16, 21, 26
2. Recursive definition
aβ = 14
aβ = 10
aβ = Β 6
aβ = Β 2
Each term (aβ) is four units less than the preceding term (aβββ)
The recursive definition is
aβ = 14, aβ = aβββ - 4