Asmall rock falling from the top of a 120 ft tall building with an intial downward velocity of -30 ft/sec is modeled by the equation h(t)=-16t-30t+124 where t is time in seconds. for which interval of time does the rock remain in the air

The rock remains in the air for t = 3.832 s

Step-by-step explanation:

To easily solve this equation, we can graph the equation with a calculator and see the interval for which the rock remains in the air.

(There is a minor problem with the equation, the last term should be 120 to model the 120 ft building)

h(t)= -16t^2 -30t + 120

Please see attached picture for the graph.

The time it takes for the ball to hit ground can be found by making

h(t) = -16t^2 -30t + 120 = 0

In the graph this point is equal to

t = 3.832 s

h(t) = 0

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant