Ineed this done asap
is the relationship shown by the data linear? if it is, write an equation for the data. if not, explain why in a sentence. x y -3 4 -1 6 1 7 3 10

lets assume line of equation is

y = mx +c

if all above points are likes on this line then it should should satisfy the equation .

so putting first two points to calculate m and c

using point (-3,4)

y = mx + c

4 = -3m+c

using 2nd point (-1, 6)

y = mx + c

6 = -m +c

subtracting eq2 from eq1

4 - 6 = -3m + c + m - c

-2 = -2m

m = 1

putting it back in eq1

4 = -3m + c

4 = -3×1 + c

c = 4+3 = 7

so equation of line is

y = 1×x+ 7

y = x + 7.

now all points except 3rd (1,7) satisfy the equation .

so data is not linear

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x