Point a has coordinates (-5,-3). what are the coordinates of the image if point a is translated five units down?

(0,-3)
(-5,2)
(-10,-3)
(-5,-8)

a(5, 3), b(2, 1), and c(-2, 4) are the coordinates of a triangle's vertices. if the triangle is translated right 5 units, what are the coordinates of the image?

a'(5, 8), b'(2, 6), c'(-2, 9)
a'(0, 3), b'(-3, 1), c'(-7, 4)
a'(10, 8), b'(7, 6), c'(3, 9)
a'(10, 3), b'(7, 1), c'(3, 4)

plz asap plz i have to turn this in now

Ques 1)

 The coordinates of the image if point A is translated five units down is:

                 (-5,-8)    

Ques 2)

   The coordinates of the image are:

     A'(10, 3), B'(7, 1), C'(3, 4)

Ques 1)

  We know that if a point which is located at (x,y) is translated some k units down that the rule for the transformation that holds is given by:

            (x,y) → (x,y-k)

Here we have: A(x,y)=(-5,-3)

and k= 5

Hence, the location of the translated point is given by:

 (-5,-3) → (-5,-3-5)

i.e.   (-5,-3) → (-5,-8)

Hence, the answer is:   (-5,-8)

Ques 2)

We know that if any points is located at (x,y) and it is translated some k units to the right then the rule for the transformation is given by:

             (x,y) → (x+k,y)

Here we have:  k=5

Hence, we get:

A( 5,3) → A'(5+5,3)    i.e.   A(5,3) → A'(10,3)

B(2,1) → B'(2+5,1)    i.e.  B(2,1) → B'(7,1)

C(-2,4) → C'(-2+5,4)   i.e.  C(-2,4) → C'(3,4)

da freeck kinda math is this just drop out

step-by-step explanation:

dont know

step-by-step explanation: