Which coordinate plane shows the graph of 3x+y> 9

well, you first must make it in slope-intercept form.

y=mx+b, or replace the = with an inequality fitting.

y> -3x+9

-3 is the slope, and 9 is the point on the y-axis in which the line must cross. since I am not provided with a graph, it is harder to explain just how to set this up. I am hoping that what I show you is enough to figure it out.

anywho, now you must focus on the inequality. using the point (0,0), replace the x and y in the inequality.

0> -3(0)+9

-3×0 is 0, and 0+9 is 9. your inequality is now 0>9, which is false.

look at your graph. the line should look similar to the first graph above (please excuse the drawing. it isnt exact to the one you should have). as you can hopefully tell, the center point is (0,0). sice the inequality is false when this point is used, it is not a solution. every point on the opposite side, where (0,0) is not located, is a solution. you shade it to look lile the second one.

ANSWER: the answer is graph A because you have to convert the equation into slope- intercept form which would be y>-3x+9

i dont know

step-by-step explanation:

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation: