An object is attached to a spring that is stretched and released. the equation d= -8*cos((pi/6)*t) models the distance, d, of the object in inches above or below the rest position as a function of time, t, in seconds. approximately when will the object be 6 inches above the rest position? round to the nearest hundredth, if necessary.

Please see the attached graph for answer.

The object will be at 6 inches above the rest position at approximately 4.62 seconds

Step-by-step explanation:

To easily solve this problem, we only need to graph the equation in a calculator and find the solution at d = 6 inches

We can see in the graph that at t = 4.62 the height is equal to d = 6.001 which is the approximation of the required value.

The graph is cyclic, because it is modeled as an harmonic oscillator without any damping.

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

cosine

step-by-step explanation: