How to sole this elimination problem
2x-5y=3
3x+4y=1

First you have to figure out the value of x in y:

2x-5y=3

2x= 3+5y

x= 3+5y /2

the substitute the x from the first problem to the second:

3(3+5y /2) +4y= 1

(9+15y/2 + 4y = 1)multiply by 2

9+15y + 8y = 2

15y+8y= 2-9

23y = -7

y = -7/23

after you get the y, substitute it to x:

x= 3 + 5(-7/23) /2

x= 3 + -35/23 /2

x= 69/23 + -35/23 /2

x= 34/23 /2

x= 34/46

dsfdsf

step-by-step explanation:

fddsf

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b