If the quadratic formula is used to solve 2x2 = 8x -3, what are the solutions

x = 2 ±

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0

Then we can solve for x using the quadratic formula

Given

2x² = 8x - 3 ( subtract 8x - 3 from both sides )

2x² - 8x + 3 = 0 ← in standard form

with a = 2, b = - 8 and c = 3, hence

x = (- (- 8) ± ) / 4

  = (8 ± ) / 4

  = (8 ± ) / 4

  = (8 ± 2 ) / 4

  = ±

  = 2 ±

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