Write an equation of the circle given its center and radius

y = x²- 4x + 3 + y²

The equation of a circle is given by the formula

(x-a)²+(x-b)² = r²

Where;  (a, b) is the center of the circle and r is the radius

Center (2,0) and radius = 1.

Therefore:

(x-2)² +(y+0) = 1²

x²- 4x + 4 + y² =  1

x²- 4x + 3 + y² =  0

Therefore; The equation of the circle is y = x²- 4x + 3 + y²

(x-2)²+ y² = 1 is the equation of given  circle.

Step-by-step explanation:

We have given the center (2,0) and radius  r = 1 of a circle.

We have to find the equation of circle.

As we know the equation of circle is :

(x - x₁)² +(y - y₁)² = r²    

Where (x₁,y₁) is the center of circle, and r is the radius of the circle.

Putting the value in above equation we get,

(x-2)²+(y-0)² = 1²

(x-2)²+ y² = 1 is the equation of given  circle.

step-by-step explanation:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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