Suppose f(x)=x^2 what is the graph of g(x)= f(5x)

Step-by-step explanation:

That '5' in f(5x) will compress the graph of x^2 horizontally.

If you were to graph f(x) = x^2, you'd get a parabolic graph; the parabola will open UP.

Suppose you graphed f(x) = x^2 on the interval [-4, 4].

Then the graph of g(x) = f(5x) would be graphed on the interval [-4/5, 4/5].  In other words, the graph would be on a shorter interval, one shorter by a factor of 5.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°