Aright triangle has an angle with a sine of 0.6. what is the cosine of the angle?
a) 0.36

b) 0.4

c) 0.64

d) 0.8

D 0.8

sin^2(x)+cos^2(x)-1

if x=0.6

then 0.6^2+cos(x)=1

cos^2=1-0.36=0.64

cos(x)=±0.8

that one

Step-by-step explanation:

becase 1, math. 2, meth. and 4, science

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°