We are using the discriminant to find how many solutions there are in the quadratic equation. i understand that if it's > 0 then 2 real solutions, =0 then 1 real solution, and < 0 no real solutions. why when a discriminant is negative there are two solutions but other times 0? explain how can you tell.

➷ If there is a negative discriminant, there won't be any real solutions. This is because two values can't be squared to give a negative value. This would mean there are no x - intercepts and also, no solutions.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

entering that problem on the tube might get you an answer

answer: both chords and diameters have two endpoints on a circle. diameters must intersect the center of a circle.