Acircle k(o) with the radius r is given. line ab tangent to circle k(o) at b. find ab, if oa= 2 cm, and r=1.5 cm.

  (√7)/2 ≈ 1.323

Step-by-step explanation:

ΔABO is a right triangle with its right angle at B. Hypotenuse OA is 2, leg OB is 1.5, so leg AB will be given by the Pythagorean theorem as ...

  AB = √(OA² -OB²) = √(2² -1.5²) = √1.75

  AB = (√7)/2 ≈ 1.323

the answer to this question is in the pic

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.