Solve the system of equations using substitution. (5 points)
-3x+2y=12
x=2y-8

x=-2 and y= 3

Step-by-step explanation:

First use x=2y-8 and put it in the other equation you will get:

-3(2y-8)+2y=12

Now distribute the -3 to whats inside the parenthesis:

-6y+24+2y=12

Combine like terms:

-4y+24=12

Subtract 24 from both sides:

-4y=36

Divide both sides by -4

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this